Identify user in a Bash script called by sudo
$SUDO_USER doesn't work if you are using sudo su -
.
It also requires multiple checks - if $USER == 'root'
then get $SUDO_USER
.
Instead of the command whoami
use who am i
. This runs the who
command filtered for the current session. It gives you more info than you need. So, do this to get just the user:
who am i | awk '{print $1}'
Alternatively (and simpler) you can use logname
. It does the same thing as the above statement.
This gives you the username that logged in to the session.
These work regardless of sudo
or sudo su [whatever]
. It also works regardless of how many times su
and sudo
are called.
I think $SUDO_USER is valid.
#!/bin/bash
echo $SUDO_USER
whoami
Here is how to get the username of the person who called the script no matter if sudo or not:
if [ $SUDO_USER ]; then user=$SUDO_USER; else user=`whoami`; fi
or a shorter version
[ $SUDO_USER ] && user=$SUDO_USER || user=`whoami`
Using whoami
, who am i
, who
, id
or $SUDO_USER
isn't right here.
Actually, who
is never a solution to the question, as it will only list the logged in users, which might be dozens...
In my eyes, the only valuable answer is the use of logname
.
Hope this helps
Rob