GROUP BY with MAX(DATE) [duplicate]

I'm trying to list the latest destination (MAX departure time) for each train in a table, for example:

Train    Dest      Time
1        HK        10:00
1        SH        12:00
1        SZ        14:00
2        HK        13:00
2        SH        09:00
2        SZ        07:00

The desired result should be:

Train    Dest      Time
1        SZ        14:00
2        HK        13:00

I have tried using

SELECT Train, Dest, MAX(Time)
FROM TrainTable
GROUP BY Train

by I got a "ora-00979 not a GROUP BY expression" error saying that I must include 'Dest' in my group by statement. But surely that's not what I want...

Is it possible to do it in one line of SQL?

SELECT train, dest, time FROM ( 
  SELECT train, dest, time, 
    RANK() OVER (PARTITION BY train ORDER BY time DESC) dest_rank
    FROM traintable
  ) where dest_rank = 1

You cannot include non-aggregated columns in your result set which are not grouped. If a train has only one destination, then just add the destination column to your group by clause, otherwise you need to rethink your query.

Try:

SELECT t.Train, t.Dest, r.MaxTime
FROM (
      SELECT Train, MAX(Time) as MaxTime
      FROM TrainTable
      GROUP BY Train
) r
INNER JOIN TrainTable t
ON t.Train = r.Train AND t.Time = r.MaxTime

Here's an example that only uses a Left join and I believe is more efficient than any group by method out there: ExchangeCore Blog

SELECT t1.*
FROM TrainTable t1 LEFT JOIN TrainTable t2
ON (t1.Train = t2.Train AND t1.Time < t2.Time)
WHERE t2.Time IS NULL;

Another solution:

select * from traintable
where (train, time) in (select train, max(time) from traintable group by train);

As long as there are no duplicates (and trains tend to only arrive at one station at a time)...

select Train, MAX(Time),
      max(Dest) keep (DENSE_RANK LAST ORDER BY Time) max_keep
from TrainTable
GROUP BY Train;