Get Max value from List<myType>
Assuming you have access to LINQ, and Age
is an int
(you may also try var maxAge
- it is more likely to compile):
int maxAge = myTypes.Max(t => t.Age);
If you also need the RandomID
(or the whole object), a quick solution is to use MaxBy
from MoreLinq
MyType oldest = myTypes.MaxBy(t => t.Age);
Okay, so if you don't have LINQ, you could hard-code it:
public int FindMaxAge(List<MyType> list)
{
if (list.Count == 0)
{
throw new InvalidOperationException("Empty list");
}
int maxAge = int.MinValue;
foreach (MyType type in list)
{
if (type.Age > maxAge)
{
maxAge = type.Age;
}
}
return maxAge;
}
Or you could write a more general version, reusable across lots of list types:
public int FindMaxValue<T>(List<T> list, Converter<T, int> projection)
{
if (list.Count == 0)
{
throw new InvalidOperationException("Empty list");
}
int maxValue = int.MinValue;
foreach (T item in list)
{
int value = projection(item);
if (value > maxValue)
{
maxValue = value;
}
}
return maxValue;
}
You can use this with:
// C# 2
int maxAge = FindMaxValue(list, delegate(MyType x) { return x.Age; });
// C# 3
int maxAge = FindMaxValue(list, x => x.Age);
Or you could use LINQBridge :)
In each case, you can return the if block with a simple call to Math.Max
if you want. For example:
foreach (T item in list)
{
maxValue = Math.Max(maxValue, projection(item));
}
int max = myList.Max(r => r.Age);
http://msdn.microsoft.com/en-us/library/system.linq.enumerable.max.aspx
var maxAge = list.Max(x => x.Age);
thelist.Max(e => e.age);