WPF WindowStartupLocation="CenterOwner" not really center, and pops all over, why?
Solution 1:
Probably because you didn't set the owner:
this.Owner = App.MainWindow; // for example
That's how I do it and it centers the window perfectly all the time.
To extend on what Will Eddins commented, you could create an overload method for ShowDialog() or Show() in your Window:
public void ShowDialog(Window owner)
{
this.Owner = owner;
this.ShowDialog();
}
public void Show(Window owner)
{
this.Owner = owner;
this.Show();
}
Or overload a constructor:
public MyWindow(Window owner)
: this()
{
this.Owner = owner;
}
Solution 2:
If you create an extention for this, you could reuse this fine idea:
/// <summary>
/// Opens a window modally, with an owner
/// </summary>
/// <param name="window">The window to open</param>
/// <param name="opener">The owner of the window getting opened</param>
/// <returns>window.ShowDialog()</returns>
public static bool? ShowDialog(this Window window, Window opener)
{
window.Owner = opener;
return window.ShowDialog();
}
Solution 3:
In addition, we can use:
this.Owner = App.Current.MainWindow;
Or Application
instead of App
.
And place it in a child window constructor:
public partial class ChildWindow : Window
{
public ChildWindow()
{
InitializeComponent();
DataContext = new ChildWindowViewModel();
this.Owner = App.Current.MainWindow;
}
}
Solution 4:
I had the same problem...but it was mostly due to the fact that, when i wanted to get rid of the child window, I used hide()
instead of close()
... so when you reopen it, because it was hidden and not closed, when the parent window is moved, it still opens at it's startup location...
So when close the child window instead of hiding it for example when finished working with it.