Series expansion for $\arctan(1-x)$
Solution 1:
When you integrate it, you get a $+C$. To get it's value, you can substitute in $x=0$ to get that $C=\arctan(1)$.
Series expansion for $\arctan(1-x)$
Solution 1:
When you integrate it, you get a $+C$. To get it's value, you can substitute in $x=0$ to get that $C=\arctan(1)$.