How to destructure option argument with all default values in ES6?
I use ES6 features with babel compiler. I have a function which takes option object as an argument:
function myFunction({ option1 = true, option2 = 'whatever' }) {
console.log(option1, option2);
// do something...
}
When I call it, destructuring happens and everything works well. I want to call it with default options most of the time, so I do:
myFunction({}); // true 'whatever'
but it looks little bit strange. It would much more cleaner just call:
myFunction(); // TypeError: Cannot read property 'option1' of undefined
Is it possible?
Solution 1:
Yes, you just have to provide a default value for the complete argument:
function myFunction({option1 = true, option2 = 'whatever'} = {}) {
// ^^^^
console.log(option1, option2);
// do something...
}