[ :Unexpected operator in shell programming [duplicate]

My code:

    #!/bin/sh
    #filename:choose.sh
    read choose
    [ "$choose" == "y" -o "$choose" == "Y" ] && echo "Yes" && exit 0
    [ "$choose" == "n" -o "$choose" == "N" ] && echo "No"  && exit 0
    echo "Wrong Input" && exit 0

But when I execute

    sh ./choose.sh

terminal prompt me that

   [: 4: n: :Unexpected operator
   [: 5: n: :Unexpected operator

Is there any mistake in my bash script? Thanks!

Solution 1:

There is no mistake in your bash script. But you are executing it with sh which has a less extensive syntax ;)

So, run bash ./choose.sh instead :)

Solution 2:

POSIX sh doesn't understand == for string equality, as that is a bash-ism. Use = instead.

The other people saying that brackets aren't supported by sh are wrong, btw.

Solution 3:

To execute it with Bash, use #!/bin/bash and chmod it to be executable, then use

./choose.sh

Solution 4:

you can use case/esac instead of if/else

case "$choose" in
  [yY]) echo "Yes" && exit;;
  [nN]) echo "No" && exit;;
  * ) echo "wrong input" && exit;;
esac

Solution 5:

you have to use bash instead or rewrite your script using standard sh

sh -c 'test "$choose" = "y" -o "$choose" = "Y"'