How to list files based on matching only part of their filename?

I have many files in a folder for example

Kiran.txt
Kiran1.txt
Kiran221.txt
Kiran144.txt
Time.csv
Timer.csv
Timer2.csv
Timer444.csv
Timer266.csv
Account.sh
Account3.sh
Account3333.sh
Account3333.sh
Account333333.sh

From this directory, I want to know how I could use grep to display files based on part of their filename - for example those starting with "Account" or those ending in ".sh".

You can find

find -type f -name "Account*"

Alternative 2 (this might include folder as well)

ls -1 Account*

Alternative 3 (grep, this could include folder as well)

ls -1 | grep -E "^Account"

Use a wildcard (What is this wildcard?):

ls *.sh

The * will match anything before the ending .sh that you want. Use the other ls options for displaying, e.g. -l to make it a long listing. See man ls for more info about what you can do with it.

Note that ls would also list any directory ending with .sh, not only files.

You can also use find to overcome this problem.

find . -type f -maxdepth 1 -name "*.sh"

This command only lists "real" files. Using find is something I'd recommend if you want to do something with the found files afterwards. You can do this with the -exec option.

The standard solution is a pipe:

ls | grep ^Account

With something as simple as "Files starting with Account", globs would also work:

ls Account*

but in general a grep is more powerful, and it doesn't run the risk of overflowing the maximum command line length if your folder is really, really full.

Use the following command

   ls *.sh