Is this self initialization valid?
Solution 1:
I'm pretty sure it's defined, and x should have the value 1. §3.6.2/1 says: "Objects with static storage duration (3.7.1) shall be zero-initialized (8.5) before any other initialization takes place."
After that, I think it's all pretty straightforward.
Solution 2:
My question is whether the behavior of the program is defined or undefined if it's valid at all. If it's defined, is the value of x known in main?
This code is definitely not clean, but to me it should work predictably.
int x
puts the variable into the data segment which is defined to be zero at the program start. Before main()
, static initializers are called. For x
that is the code x = x + 1
. x = 0 + 1 = 1
. Thus the main() would return 1.
The code would definitely work in unpredictable fashion if x
is a local variable, allocated on stack. State of stack, unlike the data segment, is pretty much guaranteed to contain undefined garbage.
Solution 3:
The 'x' variable in stored in the .bss, which is filled with 0s when you load the program. Consequently, the value of 'x' is 0 when the program gets loaded in memory.
Then before main is called, "x = x + 1" is executed.
I don't know if it's valid or not, but the behavior is not undefined.