Distinguish Chrome from Safari using jQuery.browser

It seems jQuery.browser is able to identify webkit rather easily as of 1.4. But how can I use it to distinguish Chrome from Safari (and visa-versa)?

Solution 1:

Since Sarfraz has not corrected his answer (thank you Sarfraz for pointing me in the correct direction), I will post functioning code here.

var userAgent = navigator.userAgent.toLowerCase(); 
$.browser.chrome = /chrome/.test(navigator.userAgent.toLowerCase()); 

// Is this a version of Chrome?
if($.browser.chrome){
  userAgent = userAgent.substring(userAgent.indexOf('chrome/') +7);
  userAgent = userAgent.substring(0,userAgent.indexOf('.'));
  $.browser.version = userAgent;
  // If it is chrome then jQuery thinks it's safari so we have to tell it it isn't
  $.browser.safari = false;
}

// Is this a version of Safari?
if($.browser.safari){
  userAgent = userAgent.substring(userAgent.indexOf('version/') +8);
  userAgent = userAgent.substring(0,userAgent.indexOf('.'));
  $.browser.version = userAgent;
}

Solution 2:

Without jQuery

isChrome = function() { 
  return /Chrome/.test(navigator.userAgent) && /Google Inc/.test(navigator.vendor);
}
isSafari = function() {
  return /Safari/.test(navigator.userAgent) && /Apple Computer/.test(navigator.vendor);
}

With jQuery

(Following will not work with jQuery 1.9 and above as jQuery.browser has been removed from jQuery. See http://api.jquery.com/jQuery.browser/)

$.browser.chrome = $.browser.webkit && !!window.chrome;
$.browser.safari = $.browser.webkit && !window.chrome;