How to read a file line-by-line into a list?

This code will read the entire file into memory and remove all whitespace characters (newlines and spaces) from the end of each line:

with open(filename) as file:
    lines = file.readlines()
    lines = [line.rstrip() for line in lines]

If you're working with a large file, then you should instead read and process it line-by-line:

with open(filename) as file:
    for line in file:
        print(line.rstrip())

In Python 3.8 and up you can use a while loop with the walrus operator like so:

with open(filename) as file:
    while (line := file.readline().rstrip()):
        print(line)

Depending on what you plan to do with your file and how it was encoded, you may also want to manually set the access mode and character encoding:

with open(filename, 'r', encoding='UTF-8') as file:
    while (line := file.readline().rstrip()):
        print(line)

See Input and Ouput:

with open('filename') as f:
    lines = f.readlines()

or with stripping the newline character:

with open('filename') as f:
    lines = [line.rstrip() for line in f]

This is more explicit than necessary, but does what you want.

with open("file.txt") as file_in:
    lines = []
    for line in file_in:
        lines.append(line)

This will yield an "array" of lines from the file.

lines = tuple(open(filename, 'r'))

open returns a file which can be iterated over. When you iterate over a file, you get the lines from that file. tuple can take an iterator and instantiate a tuple instance for you from the iterator that you give it. lines is a tuple created from the lines of the file.

How to read a file line-by-line into a list?

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