How can I list all vhosts in nginx

Is there a command that will list all vhosts or servers running under nginx on CentOS? I would like to pipe the results to a text file for reporting purposes.

I'm looking for something similar to this command that I use for Apache:

apachectl -S 2>&1 | grep 'port 80'

Solution 1:

starting from version 1.9.2 you can do:

nginx -T

show complete nginx configuration

nginx -T | grep "server_name " #include the whitespace to exclude non relevant results

show you all server names

Solution 2:

Update: Thanks to @Putnik for pointing out an easier way (but I prefer only listing sites-enabled):

grep server_name /etc/nginx/sites-enabled/* -RiI

Old Post:

Try something like this:

find /etc/nginx/sites-enabled/ -type f -print0 | xargs -0 egrep '^(\s|\t)*server_name'

Hope that helps!

Solution 3:

The answers so far will work, except if you have server_name directives running over multiple lines, then it'll silently fail. They also seem to be written for human consumption (picking up extra lines like server_name_in_redirect off;) so you can't include them in a script.

I have lots of virtual hosts, and wanted to use the output in a script (sigh), so here's something which is a lot longer, but should be robust enough for that purpose:

nginx -T | sed -r -e 's/[ \t]*$//' -e 's/^[ \t]*//' -e 's/^#.*$//' -e 's/[ \t]*#.*$//' -e '/^$/d' | \
sed -e ':a;N;$!ba;s/\([^;\{\}]\)\n/\1 /g' | \
grep -P 'server_name[ \t]' | grep -v '\$' | grep '\.' | \
sed -r -e 's/(\S)[ \t]+(\S)/\1\n\2/g' -e 's/[\t ]//g' -e 's/;//' -e 's/server_name//' | \
sort | uniq | xargs -L1

Since it's long and \-y, I'll include a quick explanation of each line.

1. Get nginx to print its entire configuration (so that we don't have to worry about which files to include) and sanitise it: remove leading and trailing space, comments (including trailing ones) and blank lines.
2. Every line that doesn't end with a semi-colon or curly brace should be continued, so we replace any \n without a preceding ;, { or } with a space. This needs to use sed's weirdo :a;N;$!ba; grab the whole file trick, and some grouping so that we can put the last character back with \1, plus a bunch of extra backslashes for luck.
3. Now we can pull each server_name line, with some extra checks to remove nginx variables ($foo) and only include valid domains (ie not localhost and _).
4. Any tabs/spaces between words get turned into carriage returns, then we remove surplus spaces (just in case), semi-colons and the server_name part.
5. Finally sort it, uniqify it and use xargs -L1 to remove the single blank line at the top.

Note that there are some bits in here which are technically doubling up, but I like to be as clear and robust as possible. Suggestions for improvement welcome, though.

Solution 4:

grep server_name /etc/nginx/* -RiI

Imho much faster to type than @Haubix's answer. Add |grep -v "#" optionally

Solution 5:

Beside all the other great solution, if you just need a simple list of all names one per line, like:

example.com
my.example.com
etc.com

Parse the config. Get all lines with server_name. Remove server_name. Finally put one domain per line.

sudo nginx -T | grep "server_name " | sed 's/.*server_name \(.*\);/\1/' | sed 's/ /\n/'