What does the ampersand mean in a Rust type?

Solution 1:

This means you'll be passing in a reference to the object, as opposed to moving the object itself. It's important to distinguish this because if your function looked like:

fn eat(self) {
    println!("{} is done eating.", self.name);
}

and you tried calling it then using the variable after, you'd get an error

object = Foo::new();
object.eat();
object.something(); // error, because you moved object in eat

because when you don't specify &, rust moves the value into the function and your original binding no longer has ownership. check out this minimal example I created (playground version):

struct Foo {
    x : u32
}

impl Foo {

    fn eat(self) {
        println!("eating");
    }

    fn something(&self) {
        println!("else");
    }

}

fn main() {
    println!("Hello, world!");

    let g = Foo { x: 5 };
    g.eat();
    g.something();  // if this comes before eat, no errors because we arent moving
}

Now switch something to be called before eat. Because something only takes a reference, g still has ownership and you can continue on. eat on the other hand moves g and you no longer can use g.

What does the ampersand mean in a Rust type?

Solution 1:

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