Making SVM run faster in python
Solution 1:
If you want to stick with SVC as much as possible and train on the full dataset, you can use ensembles of SVCs that are trained on subsets of the data to reduce the number of records per classifier (which apparently has quadratic influence on complexity). Scikit supports that with the BaggingClassifier
wrapper. That should give you similar (if not better) accuracy compared to a single classifier, with much less training time. The training of the individual classifiers can also be set to run in parallel using the n_jobs
parameter.
Alternatively, I would also consider using a Random Forest classifier - it supports multi-class classification natively, it is fast and gives pretty good probability estimates when min_samples_leaf
is set appropriately.
I did a quick tests on the iris dataset blown up 100 times with an ensemble of 10 SVCs, each one trained on 10% of the data. It is more than 10 times faster than a single classifier. These are the numbers I got on my laptop:
Single SVC: 45s
Ensemble SVC: 3s
Random Forest Classifier: 0.5s
See below the code that I used to produce the numbers:
import time
import numpy as np
from sklearn.ensemble import BaggingClassifier, RandomForestClassifier
from sklearn import datasets
from sklearn.multiclass import OneVsRestClassifier
from sklearn.svm import SVC
iris = datasets.load_iris()
X, y = iris.data, iris.target
X = np.repeat(X, 100, axis=0)
y = np.repeat(y, 100, axis=0)
start = time.time()
clf = OneVsRestClassifier(SVC(kernel='linear', probability=True, class_weight='auto'))
clf.fit(X, y)
end = time.time()
print "Single SVC", end - start, clf.score(X,y)
proba = clf.predict_proba(X)
n_estimators = 10
start = time.time()
clf = OneVsRestClassifier(BaggingClassifier(SVC(kernel='linear', probability=True, class_weight='auto'), max_samples=1.0 / n_estimators, n_estimators=n_estimators))
clf.fit(X, y)
end = time.time()
print "Bagging SVC", end - start, clf.score(X,y)
proba = clf.predict_proba(X)
start = time.time()
clf = RandomForestClassifier(min_samples_leaf=20)
clf.fit(X, y)
end = time.time()
print "Random Forest", end - start, clf.score(X,y)
proba = clf.predict_proba(X)
If you want to make sure that each record is used only once for training in the BaggingClassifier
, you can set the bootstrap
parameter to False.
Solution 2:
SVM classifiers don't scale so easily. From the docs, about the complexity of sklearn.svm.SVC
.
The fit time complexity is more than quadratic with the number of samples which makes it hard to scale to dataset with more than a couple of 10000 samples.
In scikit-learn you have svm.linearSVC
which can scale better.
Apparently it could be able to handle your data.
Alternatively you could just go with another classifier. If you want probability estimates I'd suggest logistic regression. Logistic regression also has the advantage of not needing probability calibration to output 'proper' probabilities.
Edit:
I did not know about linearSVC
complexity, finally I found information in the user guide:
Also note that for the linear case, the algorithm used in LinearSVC by the liblinear implementation is much more efficient than its libsvm-based SVC counterpart and can scale almost linearly to millions of samples and/or features.
To get probability out of a linearSVC
check out this link. It is just a couple links away from the probability calibration guide I linked above and contains a way to estimate probabilities.
Namely:
prob_pos = clf.decision_function(X_test)
prob_pos = (prob_pos - prob_pos.min()) / (prob_pos.max() - prob_pos.min())
Note the estimates will probably be poor without calibration, as illustrated in the link.