Sum of all real numbers $x$ such that $(\text{A quadratic})^\text{Another quadratic}=1$.
Hint
You have missed $$(-1)^{\text{even number}}=1$$
Now if $x^2-5x+5=-1,x=?$
Which values of $x$ make the exponent even?
Hint
You have missed $$(-1)^{\text{even number}}=1$$
Now if $x^2-5x+5=-1,x=?$
Which values of $x$ make the exponent even?