Get full file path in Node.js
Solution 1:
var path = require("path");
var absolutePath = path.resolve("Relative file path");
You dir structure for example:
C:->WebServer->Public->Uploads->MyFile.csv
and your working directory would be Public for example, path.resolve would be like that.
path.resolve("./Uploads/MyFile.csv");
POSIX home/WebServer/Public/Uploads/MyFile.csv
WINDOWS C:\WebServer\Public\Uploads\MyFile.csv
this solution is multiplatform and allows your application to work on both windows and posix machines.
Solution 2:
Get all files from folder and print each file description.
const path = require( "path" );
const fs = require( 'fs' );
const log = console.log;
const folder = './';
fs.readdirSync( folder ).forEach( file => {
const extname = path.extname( file );
const filename = path.basename( file, extname );
const absolutePath = path.resolve( folder, file );
log( "File : ", file );
log( "filename : ", filename );
log( "extname : ", extname );
log( "absolutePath : ", absolutePath);
});