What is the default value for Guid?
The default value for int
is 0 , for string
is "" and for boolean
it is false. Could someone please clarify what the default value for guid
is?
You can use these methods to get an empty guid. The result will be a guid with all it's digits being 0's - "00000000-0000-0000-0000-000000000000
".
new Guid()
default(Guid)
Guid.Empty
As Use Keim points out in the comments default
is short for default(Guid)
You can use Guid.Empty
. It is a read-only instance of the Guid structure with the value of 00000000-0000-0000-0000-000000000000
you can also use these instead
var g = new Guid();
var g = default(Guid);
beware not to use Guid.NewGuid()
because it will generate a new Guid.
use one of the options above which you and your team think it is more readable and stick to it. Do not mix different options across the code. I think the Guid.Empty
is the best one since new Guid()
might make us think it is generating a new guid and some may not know what is the value of default(Guid)
.
The default value for a GUID is empty. (eg: 00000000-0000-0000-0000-000000000000)
This can be invoked using Guid.Empty
or new Guid()
If you want a new GUID, you use Guid.NewGuid()
To extend answers above, you cannot use Guid default value with Guid.Empty
as an optional argument in method, indexer or delegate definition, because it will give you compile time error. Use default(Guid)
or new Guid()
instead.
Create a Empty Guid or New Guid Using a Class...
Default value of Guid is 00000000-0000-0000-0000-000000000000
public class clsGuid ---This is class Name
{
public Guid MyGuid { get; set; }
}
static void Main(string[] args)
{
clsGuid cs = new clsGuid();
Console.WriteLine(cs.MyGuid); --this will give empty Guid "00000000-0000-0000-0000-000000000000"
cs.MyGuid = new Guid();
Console.WriteLine(cs.MyGuid); ----this will also give empty Guid "00000000-0000-0000-0000-000000000000"
cs.MyGuid = Guid.NewGuid();
Console.WriteLine(cs.MyGuid); --this way, it will give new guid "d94828f8-7fa0-4dd0-bf91-49d81d5646af"
Console.ReadKey(); --this line holding the output screen in console application...
}