How can I get href links from HTML using Python?

Try with Beautifulsoup:

from BeautifulSoup import BeautifulSoup
import urllib2
import re

html_page = urllib2.urlopen("http://www.yourwebsite.com")
soup = BeautifulSoup(html_page)
for link in soup.findAll('a'):
    print link.get('href')

In case you just want links starting with http://, you should use:

soup.findAll('a', attrs={'href': re.compile("^http://")})

In Python 3 with BS4 it should be:

from bs4 import BeautifulSoup
import urllib.request

html_page = urllib.request.urlopen("http://www.yourwebsite.com")
soup = BeautifulSoup(html_page, "html.parser")
for link in soup.findAll('a'):
    print(link.get('href'))

You can use the HTMLParser module.

The code would probably look something like this:

from HTMLParser import HTMLParser

class MyHTMLParser(HTMLParser):

    def handle_starttag(self, tag, attrs):
        # Only parse the 'anchor' tag.
        if tag == "a":
           # Check the list of defined attributes.
           for name, value in attrs:
               # If href is defined, print it.
               if name == "href":
                   print name, "=", value


parser = MyHTMLParser()
parser.feed(your_html_string)

Note: The HTMLParser module has been renamed to html.parser in Python 3.0. The 2to3 tool will automatically adapt imports when converting your sources to 3.0.

Look at using the beautiful soup html parsing library.

http://www.crummy.com/software/BeautifulSoup/

You will do something like this:

import BeautifulSoup
soup = BeautifulSoup.BeautifulSoup(html)
for link in soup.findAll("a"):
    print link.get("href")