Delete the last two characters of the String [duplicate]

How can I delete the last two characters 05 of the simple string?

Simple:

"apple car 05"

Code

String[] lineSplitted = line.split(":");
String stopName = lineSplitted[0];
String stop =   stopName.substring(0, stopName.length() - 1);
String stopEnd = stopName.substring(0, stop.length() - 1);

orginal line before splitting ":"

apple car 04:48 05:18 05:46 06:16 06:46 07:16 07:46 16:46 17:16 17:46 18:16 18:46 19:16

Solution 1:

Subtract -2 or -3 basis of removing last space also.

 public static void main(String[] args) {
        String s = "apple car 05";
        System.out.println(s.substring(0, s.length() - 2));
    }

Output

apple car

Solution 2:

Use String.substring(beginIndex, endIndex)

str.substring(0, str.length() - 2);

The substring begins at the specified beginIndex and extends to the character at index (endIndex - 1)

Solution 3:

You may use the following method to remove last n character -

public String removeLast(String s, int n) {
    if (null != s && !s.isEmpty()) {
        s = s.substring(0, s.length()-n);
    }
    return s;
}

Solution 4:

You can use substring function:

s.substring(0,s.length() - 2));

With the first 0, you say to substring that it has to start in the first character of your string and with the s.length() - 2 that it has to finish 2 characters before the String ends.

For more information about substring function you can see here:

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

Solution 5:

It was almost correct just change your last line like:

String stopEnd = stop.substring(0, stop.length() - 1); //replace stopName with stop.

you can replace your last two lines;

String stopEnd =   stopName.substring(0, stopName.length() - 2);