What's the simplest way to list conflicted files in Git?

I just need a plain list of conflicted files.

Is there anything simpler than:

git ls-files -u  | cut -f 2 | sort -u

or:

git ls-files -u  | awk '{print $4}' | sort | uniq

I guess I could set up a handy alias for that, however was wondering how pros do it. I'd use it to write shell loops e.g. to auto-resolve conflict, etc. Maybe replace that loop by plugging into mergetool.cmd?

git diff --name-only --diff-filter=U

git diff --check

will show the list of files containing conflict markers including line numbers.

For example:

> git diff --check
index-localhost.html:85: leftover conflict marker
index-localhost.html:87: leftover conflict marker
index-localhost.html:89: leftover conflict marker
index.html:85: leftover conflict marker
index.html:87: leftover conflict marker
index.html:89: leftover conflict marker

source : https://ardalis.com/detect-git-conflict-markers

Trying to answer my question:

No, there doesn't seem to be any simpler way than the one in the question, out of box.

After typing that in too many times, just pasted the shorter one into an executable file named 'git-conflicts', made accessible to git, now I can just: git conflicts to get the list I wanted.

Update: as Richard suggests, you can set up an git alias, as alternative to the executable

git config --global alias.conflicts '!git ls-files -u | cut -f 2 | sort -u'

An advantage of using the executable over the alias is that you can share that script with team members (in a bin dir part of the repo).