How to print structs and arrays?
You want to implement the Debug
trait on your struct. Using #[derive(Debug)]
is the easiest solution. Then you can print it with {:?}
:
#[derive(Debug)]
struct MyStruct{
a: i32,
b: i32
}
fn main() {
let x = MyStruct{ a: 10, b: 20 };
println!("{:?}", x);
}
As mdup says, you can use Debug
, but you can also use the Display
trait.
All types can derive (automatically create) the fmt::Debug
implementation as #[derive(Debug)]
, but fmt::Display
must be manually implemented.
You can create a custom output:
struct MyStruct {
a: i32,
b: i32
}
impl std::fmt::Display for MyStruct {
fn fmt(&self, f: &mut std::fmt::Formatter) -> std::fmt::Result {
write!(f, "(value a: {}, value b: {})", self.a, self.b)
}
}
fn main() {
let test = MyStruct { a: 0, b: 0 };
println!("Used Display: {}", test);
}
Shell:
Used Display: (value a: 0, value b: 0)
For more information, you can look at the fmt
module documentation.
As no one here explicitly answers for arrays, to print out an array you need to specify the {:?}
, also used to print debug output
let val = 3;
let length = 32; // the maximum that can be printed without error
let array1d = [val; length];
let array2d = [array1d; length]; // or [[3; 32]; 32];
let array3d = [array2d; length]; // or [[[3; 32]; 32]; 32];
However arrays where length > 32
will exit with an error:
let length = 33;
let array1d = [3; length];
println("{:?}", array1d);
error[E0277]: the trait bound `[{integer}; 33]: std::fmt::Debug` is not satisfied
--> src\main.rs:6:22
|
| println!("{:?}", array1d);
| ^^^^^^^ the trait `std::fmt::Debug` is not implemented for `[{integer}; 33]`
Longer arrays can be printed out with the approach from this answer: Implement Debug trait for large array type
Actually just {:?}
is sufficient.
let a = [1, 2, 3, 4, 5];
let complete = &a[..];
println! ("{:?}", a);
println! ("{:?}", complete);