Using awk to print all columns from the nth to the last
Print all columns:
awk '{print $0}' somefile
Print all but the first column:
awk '{$1=""; print $0}' somefile
Print all but the first two columns:
awk '{$1=$2=""; print $0}' somefile
There's a duplicate question with a simpler answer using cut:
svn status | grep '\!' | cut -d\ -f2-
-d specifies the delimeter (space), -f specifies the list of columns (all starting with the 2nd)