what would the value of determinant of a matrix be if a specific entry changed?

What will the value of determinant of matrix $A=\pmatrix{1&3&4\\5&2&a\\6&-2&3}$ be change if we change $a$ to $a+2$.

This is an easy problem because $|A|=-127+20a$ and if we did that changing, we would get $-87+20a$. My question here is:

Can we do this request by doing another way? Where does that $+40$ come from regarding the whole entries of the matrix? Thanks

Solution 1:

The determinant, is after all a multilinear map on the column / row vectors.

Therefore, $$ \det\begin{pmatrix} 1&3&4 \\ 5&2&(a+2) \\6&-2&3 \end{pmatrix} = \det\begin{pmatrix} 1&3&4 \\ 5&2&a \\6&-2&3 \end{pmatrix} +\det\begin{pmatrix} 1&3&0 \\ 5&2&2 \\6&-2&0 \end{pmatrix} $$

• The determinant of the second matrix is?

• If I changed $2$ to $3$ or $4$ or $b$, the answer would be?

Solution 2:

Expand the $|A|$ along column 3.

\begin{align} |A|&= \begin{vmatrix} 1&3&4\\ 5&2&a\\ 6&-2&3 \end{vmatrix} \\ &= 4 \begin{vmatrix} 5&2\\ 6&-2 \end{vmatrix}-a \begin{vmatrix} 1&3\\ 6&-2 \end{vmatrix}+3 \begin{vmatrix} 1&3\\ 5&2 \end{vmatrix} \\ &=4(-22)-a(-20)+3(-13) \\ &=-127+20a \end{align}