Easiest way to rename a model using Django/South?
To answer your first question, the simple model/table rename is pretty straightforward. Run the command:
./manage.py schemamigration yourapp rename_foo_to_bar --empty
(Update 2: try --auto
instead of --empty
to avoid the warning below. Thanks to @KFB for the tip.)
If you're using an older version of south, you'll need startmigration
instead of schemamigration
.
Then manually edit the migration file to look like this:
class Migration(SchemaMigration):
def forwards(self, orm):
db.rename_table('yourapp_foo', 'yourapp_bar')
def backwards(self, orm):
db.rename_table('yourapp_bar','yourapp_foo')
You can accomplish this more simply using the db_table
Meta option in your model class. But every time you do that, you increase the legacy weight of your codebase -- having class names differ from table names makes your code harder to understand and maintain. I fully support doing simple refactorings like this for the sake of clarity.
(update) I just tried this in production, and got a strange warning when I went to apply the migration. It said:
The following content types are stale and need to be deleted: yourapp | foo Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'.
I answered "no" and everything seemed to be fine.
Make the changes in models.py
and then run
./manage.py schemamigration --auto myapp
When you inspect the migration file, you'll see that it deletes a table and creates a new one
class Migration(SchemaMigration):
def forwards(self, orm):
# Deleting model 'Foo'
db.delete_table('myapp_foo')
# Adding model 'Bar'
db.create_table('myapp_bar', (
...
))
db.send_create_signal('myapp', ['Bar'])
def backwards(self, orm):
...
This is not quite what you want. Instead, edit the migration so that it looks like:
class Migration(SchemaMigration):
def forwards(self, orm):
# Renaming model from 'Foo' to 'Bar'
db.rename_table('myapp_foo', 'myapp_bar')
if not db.dry_run:
orm['contenttypes.contenttype'].objects.filter(
app_label='myapp', model='foo').update(model='bar')
def backwards(self, orm):
# Renaming model from 'Bar' to 'Foo'
db.rename_table('myapp_bar', 'myapp_foo')
if not db.dry_run:
orm['contenttypes.contenttype'].objects.filter(app_label='myapp', model='bar').update(model='foo')
In the absence of the update
statement, the db.send_create_signal
call will create a new ContentType
with the new model name. But it's better to just update
the ContentType
you already have in case there are database objects pointing to it (e.g., via a GenericForeignKey
).
Also, if you've renamed some columns which are foreign keys to the renamed model, don't forget to
db.rename_column(myapp_model, foo_id, bar_id)
South can't do it itself - how does it know that Bar
represents what Foo
used to? This is the sort of thing I'd write a custom migration for. You can change your ForeignKey
in code as you've done above, and then it's just a case of renaming the appropriate fields and tables, which you can do any way you want.
Finally, do you really need to do this? I've yet to need to rename models - model names are just an implementation detail - particularly given the availability of the verbose_name
Meta option.