Can't get OkHttp's response.body.toString() to return a string
I'm trying to get some json data using OkHttp and can't figure out why when i try logging the response.body().toString()
what i get is Results:﹕ com.squareup.okhttp.Call$RealResponseBody@41c16aa8
try {
URL url = new URL(BaseUrl);
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
.url(url)
.header(/****/)
.build();
Call call = client.newCall(request);
Response response = call.execute();
**//for some reason this successfully prints out the response**
System.out.println("YEAH: " + response.body().string());
if(!response.isSuccessful()) {
Log.i("Response code", " " + response.code());
}
Log.i("Response code", response.code() + " ");
String results = response.body().toString();
Log.i("OkHTTP Results: ", results);
I don't know what i'm doing wrong here. How do i get the response string?
Solution 1:
You have use .string()
function to print the response in System.out.println()
. But at last in Log.i()
you are using .toString()
.
So please use .string()
on response body to print and get your request's response, like:
response.body().string();
NOTE:
.toString()
: This returns your object in string format..string()
: This returns your response.
I think this solve your problem... Right.
Solution 2:
Just in case someone bumps into the same weird thing as I have. I run my code during development in Debug Mode and apparently since OKHttp 2.4
..the response body is a one-shot value that may be consumed only once
So when in debug there is a call "behind the scene" from the inspector and the body is always empty. See: https://square.github.io/okhttp/3.x/okhttp/okhttp3/ResponseBody.html
Solution 3:
The response.body,.string()
can be consumed only once.
Please use as below:
String responseBodyString = response.body.string();
use the responseBodyString as needed in your application.
Solution 4:
Following is my modified CurlInterceptor. Check the end of the intercept function where I m recreating the Response object after consuming the old Response.
var responseBodyString = responseBody?.string()
response = response.newBuilder() .body( ResponseBody.create( responseBody?.contentType(), responseBodyString.toByteArray() ) ) .build()
class CurlInterceptor: Interceptor
{
var gson = GsonBuilder().setPrettyPrinting().create()
override fun intercept(chain: Interceptor.Chain): Response {
Timber.d(" **** ->>Request to server -> ****")
val request = chain.request()
var response = chain.proceed(request)
var curl = "curl -v -X ${request.method()}"
val headers = request.headers()
for ( i in 0..(headers.size() -1) ){
curl = "${curl} -H \"${headers.name(i)}: ${headers.value(i)}\""
}
val requestBody = request.body()
if (requestBody != null) {
val buffer = Buffer()
requestBody.writeTo(buffer)
var charset: Charset =
Charset.forName("UTF-8")
curl = "${curl} --data '${buffer.readString(charset).replace("\n", "\\n")}'"
}
Timber.d("$curl ${request.url()}")
Timber.d("response status code ${response.code()} message: ${response.message()}")
dumbHeaders(response)
var responseBody = response?.body()
if(responseBody != null )
{
var responseBodyString = responseBody?.string()
response = response.newBuilder()
.body(
ResponseBody.create(
responseBody?.contentType(),
responseBodyString.toByteArray()
)
)
.build()
responseBodyString = gson.toJson(responseBodyString)
Timber.d("response json -> \n $responseBodyString")
}
Timber.d(" **** << Response from server ****")
return response
}
fun dumbHeaders(response: Response) {
try {
if (response.headers() != null) {
for (headerName in response.headers().names()) {
for (headerValue in response.headers(headerName)) {
Timber.d("Header $headerName : $headerValue")
}
}
}
}
catch (ex: Exception){}
}
}
Solution 5:
Instead of using .toString() which returns an object
String results = response.body().toString();
you can use
String results = response.body().string();