Error of int cannot be dereferenced?
int
is not an object in java (it's a primitive), so you cannot invoke methods on it.
One simple way to solve it is using
Integer.toString(intArray[i])
I would write it more like this
public String[] convertToStrings(int... ints) {
String[] ret = new String[ints.length];
for(int i = 0; i < intArray.length; ++i)
ret[i] = "" + ints[i];
return ret;
}
Or in Java 8 you might write
public List<String> convertToStrings(int... ints) {
return IntStream.of(ints).mapToObj(Integer::toString).collect(toList());
}
This uses;
- Java coding conventions,
- limited scope for the variable
i
, - we do something with the
String[]
, - give the method a meaningful name,
- try to use consist formatting.
If we were worried about efficiency it is likely we could do away with the method entirely.
String.valueOf(int)
is not faster than Integer.toString(int)
. From the code in String
you can see that the String implementation just calls Integer.toString
/**
* Returns the string representation of the {@code int} argument.
* <p>
* The representation is exactly the one returned by the
* {@code Integer.toString} method of one argument.
*
* @param i an {@code int}.
* @return a string representation of the {@code int} argument.
* @see java.lang.Integer#toString(int, int)
*/
public static String valueOf(int i) {
return Integer.toString(i);
}
You code tries to call the toString() method of an int
value. In Java, int
is a primitive type and has no methods. Change the line:
Array[i] = intArray[i].toString();
to
Array[i] = String.valueOf(intArray[i]);
and the code should run. By the way, you should use lowerCamelCase for variables and fields.
Edit: For what it's worth, String.valueOf(int) is a bit faster than Integer.toString(int) on my system (Java 1.7).