Short circuit behavior of logical expressions in C in this example
Solution 1:
Precedence affects only the grouping. && has a higher precedence than || means:
++i || ++j && ++k
is equivalent to:
++i || (++j && ++k)
But that doesn't mean ++j && ++k is evaluated first. It's still evaluated left to right, and according to the short circuit rule of ||, ++i is true, so ++j && ++k is never evaluated.