Java method overloading + double dispatch

Solution 1:

The JLS states in §8.4.9 Overloading:

1. When a method is invoked (§15.12), the number of actual arguments (and any explicit type arguments) and the compile-time types of the arguments are used, at compile time, to determine the signature of the method that will be invoked (§15.12.2).
2. If the method that is to be invoked is an instance method, the actual method to be invoked will be determined at run time, using dynamic method lookup (§15.12.4).

So in your case:

1. The method argument (this) is of compile-time type Parent, and so the method print(Parent) is invoked.
2. If the Worker class was subclassed and the subclass would override that method, and the worker instance was of that subclass, then the overridden method would be invoked.

Double dispatch does not exist in Java. You have to simulate it, e.g. by using the Visitor Pattern. In this pattern, basically, each subclass implements an accept method and calls the visitor with this as argument, and this has as compile-time type that subclass, so the desired method overloading is used.

Solution 2:

The reason is that doJob is implemented in Parent and not overloaded in Child. It passes this to the worker's print methos, because this is of the type Parent the method Worker::print(Parent) will be called.

In order to have Worker::print(Parent) called you needto overload doJob in Child:

public static class Child extends Parent {
    public void doJob(Worker worker) {
        System.out.println("from Child: this is " + this.getClass().getName());

        worker.print(this);
    }
}

In the code above this.getClass() in Child is equivalent to Child.class.