Case insensitive argparse choices

Is it possible to check argparse choices in case-insensitive manner?

import argparse
choices = ["win64", "win32"]
parser = argparse.ArgumentParser()
parser.add_argument("-p", choices=choices)
print(parser.parse_args(["-p", "Win32"]))

results in:

usage: choices.py [-h] [-p {win64,win32}]
choices.py: error: argument -p: invalid choice: 'Win32' (choose from 'win64','win32')

Transform the argument into lowercase by using

type = str.lower

for the -p switch.

This solution was pointed out by chepner in a comment. The solution I proposed earlier was

type = lambda s : s.lower()

which is also valid, but it's simpler to just use str.lower.

Using lower in the type is nice way of doing this, if you don't mind loosing the case information.

If you want to retain the case, you could define a custom choices class. The choices needs two methods, __contains__ (for testing in), and iteration (to list the choices).

class mylist(list):
    # list subclass that uses lower() when testing for 'in'
    def __contains__(self, other):
        return super(mylist,self).__contains__(other.lower())
choices=mylist(['win64','win32'])
parser = argparse.ArgumentParser()
parser.add_argument("-p", choices=choices)
print(parser.parse_args(["-p", "Win32"]))
# Namespace(p='Win32')

The help is:

usage: ipython [-h] [-p {win64,win32}]

optional arguments:
  -h, --help        show this help message and exit
  -p {win64,win32}

Keeping the case information would also be possible with a one liner:

type = lambda arg: {x.lower(): x for x in choices}[arg.lower()],

Where choices would be the same list as passed to the choices parameter.