How do I pronounce "=>" as used in lambda expressions in .Net [closed]

I very rarely meet any other programmers!

My thought when I first saw the token was "implies that" since that's what it would read it as in a mathematical proof but that clearly isn't its sense.

So how do I say or read "=>" as in:-

IEnumerable<Person> Adults = people.Where(p => p.Age > 16)

Or is there even an agreed way of saying it?

I usually say 'such that' when reading that operator.

In your example, p => p.Age > 16 reads as "P, such that p.Age is greater than 16."

In fact, I asked this very question on the official linq pre-release forums, and Anders Hejlsberg responded by saying

I usually read the => operator as "becomes" or "for which". For example,
Func f = x => x * 2;
Func test = c => c.City == "London";
reads as "x becomes x * 2" and "c for which c.City equals London"

As far as 'goes to' - that's never made sense to me. 'p' isn't going anywhere.

In the case of reading code to someone, say, over the phone, then as long as they're a fellow C# programmer, I'd just use the word 'lambda' - that is, "p lambda p dot age greater-than sixteen."

In comments Steve Jessop mentioned 'maps to' in the case of transformations - so taking Anders' example:

x => x * 2;

would read

x maps to x times 2.

That does seem much closer to the actual intention of the code than 'becomes' for this case.

From MSDN:

All lambda expressions use the lambda operator =>, which is read as "goes to".

Reading Code Over the Telephone

From Eric Lippert:

I personally would say c=>c+1 as "see goes to see plus one". Some variations that I've heard:

For a projection, (Customer c)=>c.Name: "customer see becomes see dot name"

For a predicate, (Customer c)=>c.Age > 21: "customer see such that see dot age is greater than twenty-one"

I've always called it the "wang operator" :-)

"p wang age of p greater than 16"

I've seen people say, "Arrow."