Get property name and type using lambda expression

I am trying to write a function that will pull the name of a property and the type using syntax like below:

private class SomeClass
{
    Public string Col1;
}

PropertyMapper<Somewhere> propertyMapper = new PropertyMapper<Somewhere>();
propertyMapper.MapProperty(x => x.Col1)

Is there any way to pass the property through to the function without any major changes to this syntax?

I would like to get the property name and the property type.

So in the example below i would want to retrieve

Name = "Col1" and Type = "System.String"

Can anyone help?

Solution 1:

Here's enough of an example of using Expressions to get the name of a property or field to get you started:

public static MemberInfo GetMemberInfo<T, U>(Expression<Func<T, U>> expression)
{
    var member = expression.Body as MemberExpression;
    if (member != null)
        return member.Member;

    throw new ArgumentException("Expression is not a member access", "expression");
}

Calling code would look like this:

public class Program
{
    public string Name
    {
        get { return "My Program"; }
    }

    static void Main()
    {
        MemberInfo member = ReflectionUtility.GetMemberInfo((Program p) => p.Name);
        Console.WriteLine(member.Name);
    }
}

A word of caution, though: the simple statment of (Program p) => p.Name actually involves quite a bit of work (and can take measurable amounts of time). Consider caching the result rather than calling the method frequently.

Solution 2:

This can be easily done in C# 6. To get the name of property use nameof operator.

nameof(User.UserId)

and to get type of property use typeof operator.

typeof(User.UserId)

Solution 3:

I found this very useful.

public class PropertyMapper<T>
{
    public virtual PropertyInfo PropertyInfo<U>(Expression<Func<T, U>> expression)
    {
        var member = expression.Body as MemberExpression;
        if (member != null && member.Member is PropertyInfo)
            return member.Member as PropertyInfo;

        throw new ArgumentException("Expression is not a Property", "expression");
    }

    public virtual string PropertyName<U>(Expression<Func<T, U>> expression)
    {
        return PropertyInfo<U>(expression).Name;
    }

    public virtual Type PropertyType<U>(Expression<Func<T, U>> expression)
    {
        return PropertyInfo<U>(expression).PropertyType;
    }
}

I made this little class to follow the original request. If you need the name of the property you can use it like this:

PropertyMapper<SomeClass> propertyMapper = new PropertyMapper<SomeClass>();
string name = propertyMapper.PropertyName(x => x.Col1);

Solution 4:

I just thought I would put this here to build on the previous approach.

public static class Helpers
{
    public static string PropertyName<T>(Expression<Func<T>> expression)
    {
        var member = expression.Body as MemberExpression;
        if (member != null && member.Member is PropertyInfo)
            return member.Member.Name;

        throw new ArgumentException("Expression is not a Property", "expression");
    }
}

You can then call it in the following fashion:

Helpers.PropertyName(() => TestModel.TestProperty);

I should also point out that with VS 2015 and C# 6.0 you can simply use nameof.

https://msdn.microsoft.com/en-us/library/dn986596.aspx