No simple group of order $1,000,000$
Solution 1:
With $16$ Sylow $5$-subgroups, your group $G$ embeds into $S_{16}$ (indeed into $A_{16}$). But $10^6\nmid 16!$.
With $16$ Sylow $5$-subgroups, your group $G$ embeds into $S_{16}$ (indeed into $A_{16}$). But $10^6\nmid 16!$.