Visually what happens to fork() in a For Loop

Here's how to understand it, starting at the for loop.

1. Loop starts in parent, i == 0

2. Parent fork()s, creating child 1.

3. You now have two processes. Both print i=0.

4. Loop restarts in both processes, now i == 1.

5. Parent and child 1 fork(), creating children 2 and 3.

6. You now have four processes. All four print i=1.

7. Loop restarts in all four processes, now i == 2.

8. Parent and children 1 through 3 all fork(), creating children 4 through 7.

9. You now have eight processes. All eight print i=2.

10. Loop restarts in all eight processes, now i == 3.

11. Loop terminates in all eight processes, as i < 3 is no longer true.

12. All eight processes print hi.

13. All eight processes terminate.

So you get 0 printed two times, 1 printed four times, 2 printed 8 times, and hi printed 8 times.

1. Yes, it's correct. (see below)
2. No, i++ is executed after the call of fork, because that's the way the for loop works.
3. If all goes successfully, yes. However, remember that fork may fail.

A little explanation on the second one:

for (i = 0;i < 3; i++)
{
   fork();
}

is similar to:

i = 0;
while (i < 3)
{
    fork();
    i++;
}

So i in the forked processes(both parent and child) is the value before increment. However, the increment is executed immediately after fork(), so in my opinion, the diagram could be treat as correct.