Swift: Sort array of objects alphabetically
In the closure you pass to sort
, compare the properties you want to sort by. Like this:
movieArr.sorted { $0.name < $1.name }
or the following in the cases that you want to bypass cases:
movieArr.sorted { $0.name.lowercased() < $1.name.lowercased() }
Sidenote: Typically only types start with an uppercase letter; I'd recommend using name
and date
, not Name
and Date
.
Example, in a playground:
class Movie {
let name: String
var date: Int?
init(_ name: String) {
self.name = name
}
}
var movieA = Movie("A")
var movieB = Movie("B")
var movieC = Movie("C")
let movies = [movieB, movieC, movieA]
let sortedMovies = movies.sorted { $0.name < $1.name }
sortedMovies
sortedMovies
will be in the order [movieA, movieB, movieC]
Swift5 Update
channelsArray = channelsArray.sorted { (channel1, channel2) -> Bool in
let channelName1 = channel1.name
let channelName2 = channel2.name
return (channelName1.localizedCaseInsensitiveCompare(channelName2) == .orderedAscending)
With Swift 3, you can choose one of the following ways to solve your problem.
1. Using sorted(by:)
with a Movie
class that does not conform to Comparable
protocol
If your Movie
class does not conform to Comparable
protocol, you must specify in your closure the property on which you wish to use Array's sorted(by:)
method.
Movie
class declaration:
import Foundation
class Movie: CustomStringConvertible {
let name: String
var date: Date
var description: String { return name }
init(name: String, date: Date = Date()) {
self.name = name
self.date = date
}
}
Usage:
let avatarMovie = Movie(name: "Avatar")
let titanicMovie = Movie(name: "Titanic")
let piranhaMovie = Movie(name: "Piranha II: The Spawning")
let movies = [avatarMovie, titanicMovie, piranhaMovie]
let sortedMovies = movies.sorted(by: { $0.name < $1.name })
// let sortedMovies = movies.sorted { $0.name < $1.name } // also works
print(sortedMovies)
/*
prints: [Avatar, Piranha II: The Spawning, Titanic]
*/
2. Using sorted(by:)
with a Movie
class that conforms to Comparable
protocol
However, by making your Movie
class conform to Comparable
protocol, you can have a much concise code when you want to use Array's sorted(by:)
method.
Movie
class declaration:
import Foundation
class Movie: CustomStringConvertible, Comparable {
let name: String
var date: Date
var description: String { return name }
init(name: String, date: Date = Date()) {
self.name = name
self.date = date
}
static func ==(lhs: Movie, rhs: Movie) -> Bool {
return lhs.name == rhs.name
}
static func <(lhs: Movie, rhs: Movie) -> Bool {
return lhs.name < rhs.name
}
}
Usage:
let avatarMovie = Movie(name: "Avatar")
let titanicMovie = Movie(name: "Titanic")
let piranhaMovie = Movie(name: "Piranha II: The Spawning")
let movies = [avatarMovie, titanicMovie, piranhaMovie]
let sortedMovies = movies.sorted(by: { $0 < $1 })
// let sortedMovies = movies.sorted { $0 < $1 } // also works
// let sortedMovies = movies.sorted(by: <) // also works
print(sortedMovies)
/*
prints: [Avatar, Piranha II: The Spawning, Titanic]
*/
3. Using sorted()
with a Movie
class that conforms to Comparable
protocol
By making your Movie
class conform to Comparable
protocol, you can use Array's sorted()
method as an alternative to sorted(by:)
.
Movie
class declaration:
import Foundation
class Movie: CustomStringConvertible, Comparable {
let name: String
var date: Date
var description: String { return name }
init(name: String, date: Date = Date()) {
self.name = name
self.date = date
}
static func ==(lhs: Movie, rhs: Movie) -> Bool {
return lhs.name == rhs.name
}
static func <(lhs: Movie, rhs: Movie) -> Bool {
return lhs.name < rhs.name
}
}
Usage:
let avatarMovie = Movie(name: "Avatar")
let titanicMovie = Movie(name: "Titanic")
let piranhaMovie = Movie(name: "Piranha II: The Spawning")
let movies = [avatarMovie, titanicMovie, piranhaMovie]
let sortedMovies = movies.sorted()
print(sortedMovies)
/*
prints: [Avatar, Piranha II: The Spawning, Titanic]
*/
let sortArray = array.sorted(by: { $0.name.lowercased() < $1.name.lowercased() })