Will a call to std::vector::clear() set std::vector::capacity() to zero?

If I use .reserve(items) on a vector, the vector will allocate enough memory for my guess of the number of items that I'll need.

If I later on use .clear(), will that just clear the vector or save my earlier defined reserve?

thanks.

It is specified that std::vector<T>::clear() affects the size. It might not affect the capacity. For resetting the capacity, use the swap trick:

    std::vector<int> v1;

    // somehow increase capacity

    std::vector<int>().swap(v1);

Note: Since this old answer is still getting upvotes (thus people read it), I feel the need to add that C++11 has added std::vector<...>::shrink_to_fit(), which requests the vector to remove unused capacity.

It will probably not release the reserved memory although I don't think the behaviour is specified in the standard.

EDIT: Ok, just checked and the standard only says that the post-condition is that size() == 0 although I haven't come across a vector implementation that doesn't hold on to the reserved memory.

No it won't. Try it out by calling vector::capacity().

Further evidence of this is the appearance of shrink_to_fit. The standard's working draft mentions:

Remarks: shrink_to_fit is a non-binding request to reduce capacity() to size(). [ Note: The request is non-binding to allow latitude for implementation-specific optimizations. —end note ]