Java8: HashMap<X, Y> to HashMap<X, Z> using Stream / Map-Reduce / Collector

Solution 1:

Map<String, String> x;
Map<String, Integer> y =
    x.entrySet().stream()
        .collect(Collectors.toMap(
            e -> e.getKey(),
            e -> Integer.parseInt(e.getValue())
        ));

It's not quite as nice as the list code. You can't construct new Map.Entrys in a map() call so the work is mixed into the collect() call.

Solution 2:

Here are some variations on Sotirios Delimanolis' answer, which was pretty good to begin with (+1). Consider the following:

static <X, Y, Z> Map<X, Z> transform(Map<? extends X, ? extends Y> input,
                                     Function<Y, Z> function) {
    return input.keySet().stream()
        .collect(Collectors.toMap(Function.identity(),
                                  key -> function.apply(input.get(key))));
}

A couple points here. First is the use of wildcards in the generics; this makes the function somewhat more flexible. A wildcard would be necessary if, for example, you wanted the output map to have a key that's a superclass of the input map's key:

Map<String, String> input = new HashMap<String, String>();
input.put("string1", "42");
input.put("string2", "41");
Map<CharSequence, Integer> output = transform(input, Integer::parseInt);

(There is also an example for the map's values, but it's really contrived, and I admit that having the bounded wildcard for Y only helps in edge cases.)

A second point is that instead of running the stream over the input map's entrySet, I ran it over the keySet. This makes the code a little cleaner, I think, at the cost of having to fetch values out of the map instead of from the map entry. Incidentally, I initially had key -> key as the first argument to toMap() and this failed with a type inference error for some reason. Changing it to (X key) -> key worked, as did Function.identity().

Still another variation is as follows:

static <X, Y, Z> Map<X, Z> transform1(Map<? extends X, ? extends Y> input,
                                      Function<Y, Z> function) {
    Map<X, Z> result = new HashMap<>();
    input.forEach((k, v) -> result.put(k, function.apply(v)));
    return result;
}

This uses Map.forEach() instead of streams. This is even simpler, I think, because it dispenses with the collectors, which are somewhat clumsy to use with maps. The reason is that Map.forEach() gives the key and value as separate parameters, whereas the stream has only one value -- and you have to choose whether to use the key or the map entry as that value. On the minus side, this lacks the rich, streamy goodness of the other approaches. :-)

Solution 3:

A generic solution like so

public static <X, Y, Z> Map<X, Z> transform(Map<X, Y> input,
        Function<Y, Z> function) {
    return input
            .entrySet()
            .stream()
            .collect(
                    Collectors.toMap((entry) -> entry.getKey(),
                            (entry) -> function.apply(entry.getValue())));
}

Example

Map<String, String> input = new HashMap<String, String>();
input.put("string1", "42");
input.put("string2", "41");
Map<String, Integer> output = transform(input,
            (val) -> Integer.parseInt(val));

Solution 4:

Guava's function Maps.transformValues is what you are looking for, and it works nicely with lambda expressions:

Maps.transformValues(originalMap, val -> ...)

Solution 5:

Does it absolutely have to be 100% functional and fluent? If not, how about this, which is about as short as it gets:

Map<String, Integer> output = new HashMap<>();
input.forEach((k, v) -> output.put(k, Integer.valueOf(v));

(if you can live with the shame and guilt of combining streams with side-effects)