Convert Int to UInt32 in Swift

Solution 1:

You can do it easily:

var x = UInt32(yourInt)

Solution 2:

Nikos M.'s answer might overflow because Swift Ints are 64 bit now, and Swift will crash when the default UInt32 initializer overflows. If you want to avoid overflow, use the truncatingBitPattern initializer.

If you're sure your data won't overflow, then you should use the default initializer because an overflow represents invalid data for your application. If you're sure your data will overflow, but you don't care about truncation (like if you're building hash values or something) then you probably want to truncate.

let myInt: Int = 576460752303423504
let myUInt32 = UInt32(truncatingBitPattern: myInt)

Solution 3:

It's very simple:

let int: Int = 40
let uint = UInt32(i)

in your case, just pass

UInt32(Port)

For a port is not a problem, but in other cases be sure to take care of overflow

Side note: in swift it's good practice to name variables using lower camel case, so with the first letter in lowercase

Solution 4:

Still more easier: (Wondering why they use the unsigned func)

var x = Int32(yourInt)