apt-get mass install packages from a file?
Solution 1:
Something along these lines ought to do the trick.
apt-get install $(grep -vE "^\s*#" filename | tr "\n" " ")
The $(something) construction runs the something command, inserting its output in the command line.
The grep command will exclude any line beginning with a #, optionally allowing for whitespace before it. Then the tr command replaces newlines with spaces.
Solution 2:
The following command is a (slight) improvement over the alternative because sudo apt-get install is not executed when the package list is empty.
xargs -a <(awk '! /^ *(#|$)/' "$packagelist") -r -- sudo apt-get install
Note that the -a option reads items directly from a file instead of standard input. We don't want to pipe a file into xargs because stdin must remain unchanged for use by apt-get.
Solution 3:
Given a package list file package.list, try:
sudo apt-get install $(awk '{print $1'} package.list)
Solution 4:
I use this simple solution:
grep -vE '^#' file.txt | xargs sudo apt install -y
grep finds all lines that don't start with a # and gives them as arguments to sudo apt install.
Solution 5:
Well, here's my solution to install a list of packages I have for fresh install:
sudo apt install -y $(grep -o ^[^#][[:alnum:]-]* "filename")
In a bash function :
aptif () {
sudo apt install -y $(grep -o ^[^#][[:alnum:]-]* "$1")
}
grep explanation :
-
-okeep only the part of line that matches the expression -
^[^#]anything that does not start with a# -
[[:alnum]-]*a sequence of letters, numbers and-