How to reload .bashrc settings without logging out and back in again?
If I make changes to .bashrc
, how do I reload it without logging out and back in?
Solution 1:
You can enter the long form command:
source ~/.bashrc
or you can use the shorter version of the command:
. ~/.bashrc
Solution 2:
Or you could use:
exec bash
This does the same thing, and is easier to remember (at least for me).
The exec
command completely replaces the shell process by running the specified command-line. In our example, it replaces whatever the current shell is with a fresh instance of bash
(with the updated configuration files).
Solution 3:
To complement and contrast the two most popular answers, . ~/.bashrc
and exec bash
:
Both solutions effectively reload ~/.bashrc
, but there are differences:
-
. ~/.bashrc
orsource ~/.bashrc
will preserve your current shell session:- Except for the modifications that reloading
~/.bashrc
into the current shell (sourcing) makes, the current shell process and its state are preserved, which includes environment variables, shell variables, shell options, shell functions, and command history.
- Except for the modifications that reloading
-
exec bash
, or, more robustly,exec "$BASH"
[1], will replace your current shell with a new instance, and therefore only preserve your current shell's environment variables (including ones you've defined ad hoc, in-session).- In other words: Any ad-hoc changes to the current shell in terms of shell variables, shell functions, shell options, command history are lost.
Depending on your needs, one or the other approach may be preferred.
Note: The above applies analogously to other shells too:
- To apply the
exec
approach to whatever your default shell is, useexec $SHELL
- Similarly, the sourcing approach requires you to know and specify the name of the shell-specific initialization file; e.g., for
zsh
:. ~/.zshrc
[1] exec bash
could in theory execute a different bash
executable than the one that started the current shell, if it happens to exist in a directory listed earlier in the $PATH
. Since special variable $BASH
always contains the full path of the executable that started the current shell, exec "$BASH"
is guaranteed to use the same executable.
A note re "..."
around $BASH
: double-quoting ensures that the variable value is used as-is, without interpretation by Bash; if the value has no embedded spaces or other shell metacharacters (which is likely in this case), you don't strictly need double quotes, but using them is a good habit to form.
Solution 4:
Someone edited my answer to add incorrect English, but here was the original, which is inferior to the accepted answer.
. .bashrc