How can I get the named parameters from a URL using Flask?

When the user accesses this URL running on my flask app, I want the web service to be able to handle the parameters specified after the question mark:

http://10.1.1.1:5000/login?username=alex&password=pw1

#I just want to be able to manipulate the parameters
@app.route('/login', methods=['GET', 'POST'])
def login():
    username = request.form['username']
    print(username)
    password = request.form['password']
    print(password)

Solution 1:

Use request.args to get parsed contents of query string:

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

Solution 2:

The URL parameters are available in request.args, which is an ImmutableMultiDict that has a get method, with optional parameters for default value (default) and type (type) - which is a callable that converts the input value to the desired format. (See the documentation of the method for more details.)

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)

Examples with the code above:

/my-route?page=34               -> page: 34  filter: '*'
/my-route                       -> page:  1  filter: '*'
/my-route?page=10&filter=test   -> page: 10  filter: 'test'
/my-route?page=10&filter=10     -> page: 10  filter: '10'
/my-route?page=*&filter=*       -> page:  1  filter: '*'

Solution 3:

You can also use brackets <> on the URL of the view definition and this input will go into your view function arguments

@app.route('/<name>')
def my_view_func(name):
    return name