Shadowing and Nested function
Your code is equivalent to the following, where I've simply numbered instances of your names to help you visualize how shadowing is occurring.
let func y0 =
let dup0 y1 = y1 + y1
let z0 = dup0 y0
let dup1 y2 =
let dup2 z1 =
let y3 = y2 * z1
y3
let z2 = y2
y2
dup1 z0 + z0
This can be further simplified, of course. Since dup2
and z2
are never used, dup1
is equivalent to let dup1 y2 = y2
, and the whole function is equivalent to
let func y0 =
let dup0 y1 = y1 + y1
let z0 = dup0 y0
dup1 z0 + z0
Which is equivalent to
let func y0 =
let z0 = y0 + y0
z0 + z0
by substitution. This is the same as
let func y0 = 4 * y0
Does this help?
I think @kvb gives a very good explanation showing how the code evaluates. The code combines nested functions and shadowing in a pretty confusing way :-). I think it is useful to look at the two concepts separately.
Shadowing allows you to hide a value by a new value in the let
declaration or a value binding in the match
construct. It means that you'll no longer be able to access the original value. Here is a simpler example:
let foo num =
let num = num + 20 // Line 2
let num = num * 2 // Line 3
num
Here, we declare a function that takes an argument named num
. Let's say we call the function with 1 as the argument. On the second line, we declare a new value with the same name - initialized to 1 + 20 which is 21. The third line again declares a new value and initializes it to 21 * 2 (because it sees the last declared num symbol, which has value 21). On the line 4, we again access the last declared num symbol and we return 42.
This is useful mainly whan you have some calculation that calculates some new value that should be use by all subsequent calculations. Shadowing allows you to hide the previous value, so there is no danger you will accidentaly use the original one.
Nested functions are quite useful when you need to do some local utility calculation that uses parameters of the outer function. For example:
let times x nums =
let timesUtil y = y * x
for n in nums do
printfn "%d" (timesUtil n)
Here we declare a utility nested function timesUtil
that multiplies any number by the value x
(which is the argument of the times
function). Then we can use it later (on the last line) to do the operation without having to pass the x
value as an argument again. So, the main interesting thing about nested functions is that they can access values declared by the outer function.