grep "something" anyfiles.log > afile.csv , don't need to print the input path and file name to CSV file

I have some logs files, they have more than 30000 lines. I need to find the name "domain" and save in CSV file but after saving, any lines in CSV file has been added the path and file name of input files at the beginning of very line of CSV file. How can I do if I don't need the path and input file name add to CSV files.

Example:

Input
#cat /home/log/any.log

any things..domain, anything
any things..domain, anything
any things..domain, anything


grep "domain" /home/logs/any.log > newfile.csv

Output:
#cat newfile.csv
/home/logs/any.log:domain
/home/logs/any.log:domain
/home/logs/any.log:domain


#----My requirement output is:

cat newfile.csv
domain
domain
domain

Kind regards, please help me if anyone knowns

Use the --no-filename option for grep.

Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.

grep --no-filename "domain" 

Reference: Grep Manual

See man cut for details, but the short answer is grep "domain" /home/logs/*.log | cut -d: -f2 >newfile.csv.

Or see man grep and do grep -o "domain" /home/logs/*.log >newfile.csv

PS: grep does NOT output the filename if there's only ONE file on the command line, like grep "domain" /home/logs/any.log in your example. If you want to force filenames to be output, grep "domain" /home/logs/any.log /dev/null will do the trick.