C# Double - ToString() formatting with two decimal places but no rounding

I use the following:

double x = Math.Truncate(myDoubleValue * 100) / 100;

For instance:

If the number is 50.947563 and you use the following, the following will happen:

- Math.Truncate(50.947563 * 100) / 100;
- Math.Truncate(5094.7563) / 100;
- 5094 / 100
- 50.94

And there's your answer truncated, now to format the string simply do the following:

string s = string.Format("{0:N2}%", x); // No fear of rounding and takes the default number format

The following rounds the numbers, but only shows up to 2 decimal places (removing any trailing zeros), thanks to .##.

decimal d0 = 24.154m;
decimal d1 = 24.155m;
decimal d2 = 24.1m;
decimal d3 = 24.0m;

d0.ToString("0.##");   //24.15
d1.ToString("0.##");   //24.16 (rounded up)
d2.ToString("0.##");   //24.1  
d3.ToString("0.##");   //24

http://dobrzanski.net/2009/05/14/c-decimaltostring-and-how-to-get-rid-of-trailing-zeros/

I suggest you truncate first, and then format:

double a = 123.4567;
double aTruncated = Math.Truncate(a * 100) / 100;
CultureInfo ci = new CultureInfo("de-DE");
string s = string.Format(ci, "{0:0.00}%", aTruncated);

Use the constant 100 for 2 digits truncate; use a 1 followed by as many zeros as digits after the decimal point you would like. Use the culture name you need to adjust the formatting result.