How to print the values of slices

Solution 1:

You can try the %v, %+v or %#v verbs of go fmt:

fmt.Printf("%v", projects)

If your array (or here slice) contains struct (like Project), you will see their details.
For more precision, you can use %#v to print the object using Go-syntax, as for a literal:

%v  the value in a default format.
    when printing structs, the plus flag (%+v) adds field names
%#v a Go-syntax representation of the value

For basic types, fmt.Println(projects) is enough.

Note: for a slice of pointers, that is []*Project (instead of []Project), you are better off defining a String() method in order to display exactly what you want to see (or you will see only pointer address).
See this play.golang example.

Solution 2:

For a []string, you can use strings.Join():

s := []string{"foo", "bar", "baz"}
fmt.Println(strings.Join(s, ", "))
// output: foo, bar, baz

Solution 3:

I prefer fmt.Printf("%+q", arr) which will print

["some" "values" "list"]

https://play.golang.org/p/XHfkENNQAKb

Solution 4:

If you just want to see the values of an array without brackets, you can use a combination of fmt.Sprint() and strings.Trim()

a := []string{"a", "b"}
fmt.Print(strings.Trim(fmt.Sprint(a), "[]"))
fmt.Print(a)

Returns:

a b
[a b]

Be aware though that with this solution any leading brackets will be lost from the first value and any trailing brackets will be lost from the last value

a := []string{"[a]", "[b]"}
fmt.Print(strings.Trim(fmt.Sprint(a), "[]")
fmt.Print(a)

Returns:

a] [b
[[a] [b]]

For more info see the documentation for strings.Trim()