How do I choose the URL for my Spring Boot webapp?

I am using Spring Boot to create a web app, and I am not sure how to change the URL from localhost:8080 to something like localhost:8080/myWebApp.

I have a seen a lot of resources online referencing an application.properties file and adding that to the classpath. But, I'm not sure exactly where to put that.

Questions

• In my src/main/resources?

• How would I assign the URL within the file?

Solution 1:

You need to set the property server.contextPath to /myWebApp.

Check out this part of the documentation

The easiest way to set that property would be in the properties file you are using (most likely application.properties) but Spring Boot provides a whole lot of different way to set properties. Check out this part of the documentation

EDIT

As has been mentioned by @AbdullahKhan, as of Spring Boot 2.x the property has been deprecated and should be replaced with server.servlet.contextPath as has been correctly mentioned in this answer.

Solution 2:

As of spring boot 2 the server.contextPath property is deprecated. Instead you should use server.servlet.contextPath.

So in your application.properties file add:

server.servlet.contextPath=/myWebApp

For more details see: https://github.com/spring-projects/spring-boot/wiki/Spring-Boot-2.0-Migration-Guide#servlet-specific-server-properties

Solution 3:

In your src/main/resources put an application.properties or application.yml and put a server.contextPath in there.

server.contextPath=/your/context/here

When starting your application the application will be available at http://localhost:8080/your/context/here.

For a comprehensive list of properties to set see Appendix A. of the Spring Boot reference guide.

Instead of putting it in the application.properties you can also pass it as a system property when starting your application

java -jar yourapp.jar -Dserver.contextPath=/your/path/here