sigmoid $\circ$ sigmoid = sigmoid?
Define $g(x)=10\tanh(x/10)+\tanh(10x)$ and $f(x)=g(x-5)$.
$g(x)$:
$g'(x):$
$g''(x):$
$f(g(x)):$
Note that despite how the graphs look, all derivatives are obviously bounded.
Define $g(x)=10\tanh(x/10)+\tanh(10x)$ and $f(x)=g(x-5)$.
$g(x)$:
$g'(x):$
$g''(x):$
$f(g(x)):$
Note that despite how the graphs look, all derivatives are obviously bounded.