How to remove all subviews of a view in Swift?

I'm looking for a simple method to remove at once all subviews from a superview instead of removing them one by one.

//I'm trying something like this, but is not working
let theSubviews : Array = container_view.subviews
for (view : NSView) in theSubviews {
    view.removeFromSuperview(container_view)
}

What I am missing?

UPDATE

My app has a main container_view. I have to add different other views as subviews to container_view in order to provide a sort of navigation.

So, when clicking the button to "open" a particular page, I need to remove allsubviews and add the new one.

UPDATE 2 - A working solution (OS X)

I guess Apple fixed it.

Now it is more easy than ever, just call:

for view in containerView.subviews{
    view.removeFromSuperview()
}

Solution 1:

EDIT: (thanks Jeremiah / Rollo)

By far the best way to do this in Swift for iOS is:

view.subviews.forEach({ $0.removeFromSuperview() }) // this gets things done
view.subviews.map({ $0.removeFromSuperview() }) // this returns modified array

^^ These features are fun!

let funTimes = ["Awesome","Crazy","WTF"]
extension String { 
    func readIt() {
        print(self)
    }
}

funTimes.forEach({ $0.readIt() })

//// END EDIT

Just do this:

for view in self.view.subviews {
    view.removeFromSuperview()
}

Or if you are looking for a specific class

for view:CustomViewClass! in self.view.subviews {
        if view.isKindOfClass(CustomViewClass) {
            view.doClassThing()
        }
    }

Solution 2:

For iOS/Swift, to get rid of all subviews I use:

for v in view.subviews{
   v.removeFromSuperview()
}

to get rid of all subviews of a particular class (like UILabel) I use:

for v in view.subviews{
   if v is UILabel{
      v.removeFromSuperview()
   }
}