Code Golf: Triforce
This is inspired by/taken from this thread: http://www.allegro.cc/forums/thread/603383
The Problem
Assume the user gives you a numeric input ranging from 1 to 7. Input should be taken from the console, arguments are less desirable.
When the input is 1, print the following:
***********
*********
*******
*****
***
*
Values greater than one should generate multiples of the pattern, ending with the one above, but stacked symmetrically. For example, 3 should print the following:
*********** *********** ***********
********* ********* *********
******* ******* *******
***** ***** *****
*** *** ***
* * *
*********** ***********
********* *********
******* *******
***** *****
*** ***
* *
***********
*********
*******
*****
***
*
Bonus points if you print the reverse as well.
*********** ***********
********* *********
******* *******
***** *****
*** ***
* *
***********
*********
*******
*****
***
*
*
***
*****
*******
*********
***********
* *
*** ***
***** *****
******* *******
********* *********
*********** ***********
Can we try and keep it to one answer per language, that we all improve on?
Solution 1:
Assembler, 165 bytes assembled
Build Instructions
- Download A86 from here
- Add a reference to the A86 executable into your DOS search path
- Paste the code below into a text file (example:
triforce.asm
) - Invoke the assembler:
a86 triforce.asm
- This will create a .COM file called
triforce.com
- Type
triforce
to run
This was developed using the standard WinXP DOS box (Start->Programs->Accessories->Command Prompt). It should work with other DOS emulators.
Assemble using A86 and requires WinXP DOS box to run the .COM file it produces. Press 'q' to exit, keys 1-7 to draw the output.
l20:mov ah,7
int 21h
cmp al,'q'
je ret
sub al,'0'
cmp al,1
jb l20
cmp al,7
ja l20
mov [l0-1],al
mov byte ptr [l7+2],6
jmp $+2
mov ah,2
mov ch,0
mov bh,3
l0:mov bl,1
l1:mov dh,0
l3:cmp dh,ch
je l2
mov dl,32
int 21h
inc dh
jmp l3
ret
l2:mov dh,bh
l6:mov cl,12
l5:mov dl,42
cmp cl,bl
ja l4
mov dl,32
cmp dh,1
je l21
l4:int 21h
dec cl
jnz l5
l21:dec dh
jnz l6
mov dl,10
int 21h
mov dl,13
int 21h
l10:inc ch
l9:add bl,2
l7:cmp ch,6
jne l1
l13:add byte ptr [l7+2],6
l11:dec bh
l12:cmp bh,0
jne l0
xor byte ptr [l0+1],10
xor byte ptr [l9+1],40
xor byte ptr [l10+1],8
xor byte ptr [l13+1],40
sub byte ptr [l7+2],12
mov dh,[l0-1]
inc dh
xor [l12+2],dh
xor byte ptr [l11+1],8
xor byte ptr [l1+1],1
inc bh
cmp byte ptr [l0+1],11
je l0
jmp l20
It uses lots of self-modifying code to do the triforce and its mirror, it even modifies the self-modifying code.
Solution 2:
GolfScript - 43 chars
~:!6*,{:^' '
*'*'12*' '
^6%.+)*+
-12>!^
6/-*
n}
/
~:!6*,{:^' '*'*'12*' '^6%.+)*+-12>!^6/-*n}/
48 Chars for the bonus
~:!6*,.-1%+{
:^' '*'*'12
*' '^6%.+
)*+-12>
!^6/-
*n}
/
~:!6*,.-1%+{:^' '*'*'12*' '^6%.+)*+-12>!^6/-*n}/