How to implement two inits with same content without code duplication in Swift?
What we need is a common place to put our initialization code before calling any superclass's initializers, so what I currently using, shown in a code below. (It also cover the case of interdependence among defaults and keep them constant.)
import UIKit
class MyView: UIView {
let value1: Int
let value2: Int
enum InitMethod {
case coder(NSCoder)
case frame(CGRect)
}
override convenience init(frame: CGRect) {
self.init(.frame(frame))!
}
required convenience init?(coder aDecoder: NSCoder) {
self.init(.coder(aDecoder))
}
private init?(_ initMethod: InitMethod) {
value1 = 1
value2 = value1 * 2 //interdependence among defaults
switch initMethod {
case let .coder(coder): super.init(coder: coder)
case let .frame(frame): super.init(frame: frame)
}
}
}
I just had the same problem.
As GoZoner said, marking your variables as optional will work. It's not a very elegant way because you then have to unwrap the value each time you want to access it.
I will file an enhancement request with Apple, maybe we could get something like a "beforeInit" method that is called before every init where we can assign the variables so we don't have to use optional vars.
Until then, I will just put all assignments into a commonInit method which is called from the dedicated initialisers. E.g.:
class GradientView: UIView {
var gradientLayer: CAGradientLayer? // marked as optional, so it does not have to be assigned before super.init
func commonInit() {
gradientLayer = CAGradientLayer()
gradientLayer!.frame = self.bounds
// more setup
}
init(coder aDecoder: NSCoder!) {
super.init(coder: aDecoder)
commonInit()
}
init(frame: CGRect) {
super.init(frame: frame)
commonInit()
}
override func layoutSubviews() {
super.layoutSubviews()
gradientLayer!.frame = self.bounds // unwrap explicitly because the var is marked optional
}
}
Thanks to David I had a look at the book again and I found something which might be helpful for our deduplication efforts without having to use the optional variable hack. One can use a closure to initialize a variable.
Setting a Default Property Value with a Closure or Function
If a stored property’s default value requires some customization or setup, you can use a closure or global function to provide a customized default value for that property. Whenever a new instance of the type that the property belongs to is initialized, the closure or function is called, and its return value is assigned as the property’s default value. These kinds of closures or functions typically create a temporary value of the same type as the property, tailor that value to represent the desired initial state, and then return that temporary value to be used as the property’s default value.
Here’s a skeleton outline of how a closure can be used to provide a default property value:
class SomeClass { let someProperty: SomeType = { // create a default value for someProperty inside this closure // someValue must be of the same type as SomeType return someValue }() }
Note that the closure’s end curly brace is followed by an empty pair of parentheses. This tells Swift to execute the closure immediately. If you omit these parentheses, you are trying to assign the closure itself to the property, and not the return value of the closure.
NOTE
If you use a closure to initialize a property, remember that the rest of the instance has not yet been initialized at the point that the closure is executed. This means that you cannot access any other property values from within your closure, even if those properties have default values. You also cannot use the implicit self property, or call any of the instance’s methods.
Excerpt From: Apple Inc. “The Swift Programming Language.” iBooks. https://itun.es/de/jEUH0.l
This is the way I will use from now on, because it does not circumvent the useful feature of not allowing nil on variables. For my example it'll look like this:
class GradientView: UIView {
var gradientLayer: CAGradientLayer = {
return CAGradientLayer()
}()
func commonInit() {
gradientLayer.frame = self.bounds
/* more setup */
}
init(coder aDecoder: NSCoder!) {
super.init(coder: aDecoder)
commonInit()
}
init(frame: CGRect) {
super.init(frame: frame)
commonInit()
}
}
How about this?
public class MyView : UIView
{
var myImageView: UIImageView = UIImageView()
private func setup()
{
myImageView.contentMode = UIViewContentMode.ScaleAspectFill
}
override public init(frame: CGRect)
{
super.init(frame: frame)
setup()
}
required public init(coder aDecoder: NSCoder)
{
super.init(coder: aDecoder)
setup()
}
}
Does it necessarily have to come before? I think this is one of the things implicitly unwrapped optionals can be used for:
class MyView: UIView {
var myImageView: UIImageView!
init(frame: CGRect) {
super.init(frame: frame)
self.commonInit()
}
init(coder aDecoder: NSCoder!) {
super.init(coder: aDecoder)
self.commonInit()
}
func commonInit() {
self.myImageView = UIImageView(frame: CGRectZero)
self.myImageView.contentMode = UIViewContentMode.ScaleAspectFill
}
...
}
Implicitly unwrapped optionals allow you skip variable assignment before you call super
. However, you can still access them like normal variables:
var image: UIImageView = self.myImageView // no error
Yet another option using a static method (added 'otherView' to highlight scalability)
class MyView: UIView {
var myImageView: UIImageView
var otherView: UIView
override init(frame: CGRect) {
(myImageView,otherView) = MyView.commonInit()
super.init(frame: frame)
}
required init(coder aDecoder: NSCoder) {
(myImageView, otherView) = MyView.commonInit()
super.init(coder: aDecoder)!
}
private static func commonInit() -> (UIImageView, UIView) {
//do whatever initialization stuff is required here
let someImageView = UIImageView(frame: CGRectZero)
someImageView.contentMode = UIViewContentMode.ScaleAspectFill
let someView = UIView(frame: CGRect(x: 0, y: 0, width: 30, height: 30))
return (someImageView, someView)
}
}