How to display image from database using php [duplicate]

I am trying to display an image coming from the database and I was not able to display the image .but its showing like this user-1.jpg Please see my code can one guide me how to display the image.

$sqlimage = "SELECT image FROM userdetail where `id` = $id1";
$imageresult1 = mysql_query($sqlimage);

while($rows = mysql_fetch_assoc($imageresult1))
{       
    $image = $rows['image'];    
    print $image;
}

Displaying an image from MySql Db.

$db = mysqli_connect("localhost","root","","DbName"); 
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$result=mysqli_fetch_array($sth);
echo '<img src="data:image/jpeg;base64,'.base64_encode( $result['image'] ).'"/>';

For example if you use this code , you can load image from db (mysql) and display it in php5 ;)

<?php
   $con =mysql_connect("localhost", "root" , "");
   $sdb= mysql_select_db("my_database",$con);
   $sql = "SELECT * FROM `news` WHERE 1";
   $mq = mysql_query($sql) or die ("not working query");
   $row = mysql_fetch_array($mq) or die("line 44 not working");
   $s=$row['photo'];
   echo $row['photo'];

   echo '<img src="'.$s.'" alt="HTML5 Icon" style="width:128px;height:128px">';
   ?>

<?php
       $connection =mysql_connect("localhost", "root" , "");
       $sqlimage = "SELECT * FROM userdetail where `id` = '".$id1."'";
      $imageresult1 = mysql_query($sqlimage,$connection);

      while($rows = mysql_fetch_assoc($imageresult1))
    {       
       echo'<img height="300" width="300" src="data:image;base64,'.$rows['image'].'">';
    }
    ?>